2x-264+2x^2=0

Solution for 2x-264+2x^2=0 equation:

2x-264+2x^2=0

a = 2; b = 2; c = -264;
Δ = b2-4ac
Δ = 22-4·2·(-264)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-46}{2*2}=\frac{-48}{4}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+46}{2*2}=\frac{44}{4}
=11
$